The angle between the tangents drawn from the | vedclass

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Question

Let the equation of tangent drawn from (0,0) to the circle be $y=m x$. Then, $p=a \Rightarrow \frac{7 m+1}{\sqrt{m^{2}+1}}=5$

$\Rightarrow 24 m^{2}

Vedclass · Accepted Answer

$\frac{\pi}{2}$

Vedclass · Answer

Let the equation of tangent drawn from (0,0) to the circle be $y=m x$. Then, $p=a \Rightarrow \frac{7 m+1}{\sqrt{m^{2}+1}}=5$

$\Rightarrow 24 m^{2}+14 m-24=0$

$\Rightarrow 12 m^{2}+7 m-12=0$

$\Rightarrow m_{1} m_{2}=\frac{-12}{12}=-1$

$\because$ Required angle $=\frac{\pi}{2}$

The angle between the tangents drawn from the origin to the circle $(x -7)^2 + (y + 1)^2 = 25$ is :-

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